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計算多項式 f(x)=a_0x~n+a_1x~(n-1)+a_2x~(n-2)+ … +a_(n-1)x+a_n的值。如所週知,可以用下面的方法ropnp来完成: P_0=a_0,P_1=P_0x+a_1,P_2=P_1x+a_2,…, …,P_n=P_(n-1)x+a_n=f(x)。这些过渡的值P_1,P_2,…和最終的值可以用下面的方式几何地得到: (1)在与OX軸构成銳角的OY軸上,取(在正的方向)尺标綫段OM,通过点M引垂直于OX軸的直线ν。在OY軸上取线段OS,OS对应于要求算出f(x)的x值,(于是(?))过点S引出平行于OX軸的直线并与直线ν交于点P。直线OP在下面的研究中将起基础的作用, (2)在OY軸上取OO_0=a_0(較准确地說(?)
The value of the polynomial f(x)=a_0x~n+a_1x~(n-1)+a_2x~(n-2)+ ... +a_(n-1)x+a_n is calculated. As is well known, it can be accomplished by the following method ropnp: P_0=a_0, P_1=P_0x+a_1, P_2=P_1x+a_2,...,..., P_n=P_(n−1)x+a_n=f(x) . The values of the transitions P_1, P_2,..., and the final values can be geometrically obtained as follows: (1) On the OY axis forming an acute angle with the OX axis, take (in the positive direction) the scale segment OM, passing through Point M leads to a straight line ν perpendicular to the OX axis. The line OS is taken on the OY axis, and OS corresponds to the value of x required to calculate f(x). (Thus (?)) leads the line parallel to the OX axis through the point S and intersects the line ν at the point P. The linear OP will play a fundamental role in the following study. (2) Take OO_0=a_0 on the OY axis (more precisely, (?)