【题目】火车以速度v1匀速行驶,司机发现前方同轨道上相距s处有另一火车沿同方向以速度v(2对地v1>v2)做匀速运动,司机立即以加速度a紧急刹车,要使两车不想撞,a应满足什么条件?【分析】两车不相撞的临界条件是:二者速度相等时刚好追上,由此可得二者的“位移”关系与“速度关系”方程,这样才能使问题得到解决。 [Title] The train travels at a constant speed v1. The driver finds that there is another train in the same direction at the distance s from the front with the speed v (2 v1>v2). The driver immediately accelerates with an acceleration. The two cars do not want to hit, a What conditions should be met? [Analysis] The critical condition of the two cars do not collide is: When the two speeds are equal, just to catch up, which can get the “displacement” relationship and “ Speed ​​relationship ” equations, so that the problem can be solved.