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该文对辣根过氧化物酶(HRP)催化聚合去除水中双酚A(BPA)进行实验研究,考察[H_2O_2]∶[BPA]摩尔比、酶活力和腐殖酸(HA)浓度对BPA去除的影响。结果表明,提高过氧化氢浓度和酶活力能够提高BPA去除率,同时降低水中中间产物A的浓度。在[BPA]10 mg/L、[HRP]0.2 U/mL、[H_2O_2]∶[BPA]为1∶1,pH 7和25℃的条件下反应30 min,当水中存在2~10 mg/L HA情况下,BPA去除率从62.2%提高至90%以上。推测机理如下:加入适量的HA后,HA与BPA发生交叉偶联反应,增大BPA去除率,当HA加入量过大后,HA可能发生自聚合反应,对BPA与HA交叉偶联反应产生竞争作用。
In this paper, bisphenol A (BPA) was removed by catalytic polymerization of horseradish peroxidase (HRP). The effects of [H_2O_2]: [BPA] molar ratio, enzyme activity and humic acid (HA) Impact. The results showed that increasing the hydrogen peroxide concentration and enzyme activity increased BPA removal while decreasing the concentration of intermediate A in the water. Under the conditions of [BPA] 10 mg / L, [HRP] 0.2 U / mL, [H 2 O 2]: [BPA] 1: 1, pH 7 and 25 ℃ for 30 min, In the case of HA, the BPA removal rate increased from 62.2% to over 90%. The reasoning mechanism is as follows: After adding appropriate amount of HA, HA and BPA cross-coupling reaction, increasing BPA removal rate, when the amount of HA is too large, HA may occur self-polymerization reaction of BPA and HA cross-coupling reaction to compete effect.