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二、計算算例以专桥1014步充图l_P=16.0m低高度梁直线梁为例 1. 设计资料混凝土等级:400级容许压应力〔σσ-2〕=140kg/cm~2,工厂制造可提高10％。则〔σσ-2〕＇=1.1×140=154kg/cm~2。容许剪应力:〔l〕=R_P=22kg/cm~2。矢蹬筋及斜筋时的斜拉应力R_(p-1)=8.2kg/cm~3。钢筋:采用16錳作主要受力钢筋。容许应力〔σα〕=1600kg/cm~2(考虑到焊接疲劳折减后数值) 各截面之力矩及剪力(查前面表一,三※注:載于本刊九～十期)。跨中截面: 弯矩M=244+151.2=395.2t-m 剪力Q=22.00t 变截面处: (距支点4.0m) 剪力Q=43.25+18.88=62.13t 支点截面: 剪力Q=70.40+37.80=108.2t
Second, the calculation example to the special bridge 1014 step charge Figure l_P = 16.0m low height beam straight beam as an example 1. Design information Concrete grade: 400 allowable compressive stress [σσ-2] = 140kg / cm ~ 2, the factory can be Increase by 10%. Σσ-2] = 1.1 × 140 = 154 kg / cm 2. Allowable shear stress: [l] = R_P = 22kg / cm ~ 2. Radial tensile stress when the tendons tendons and oblique tendons R_ (p-1) = 8.2kg / cm ~ 3. Reinforced steel: 16 manganese as the main force of steel. Allowable stress 〔σα〕 = 1600kg / cm ~ 2 (taking into account the value of the welding fatigue reduction) of each section of the moment and shear force (check the front table one, three ※ Note: contained in this issue nine to ten). Cross-section: Moment M = 244 + 151.2 = 395.2tm Shear Q = 22.00t At the cross section: (4.0m from the fulcrum) Shear Q = 43.25 + 18.88 = 62.13t Fulcrum section: Shear Q = 70.40 + 37.80 = 108.2t