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问题.在如图1所示的电路中,理想变压器原、副线圈的匝数比n1∶n2=22∶5,原线圈接u1=220槡2sin100πt(V)的交流电,电阻R1=R2=25Ω,D为理想二极管,则下述正确的是(A)电阻R1两端的电压为50V.(B)二极管的反向耐压值应大于50槡2V.(C)原线圈的输入功率为200W.(D)通过副线圈的电流为3A.这是江苏省南通市2013届高三第一次调研测试中的第8题.参考答案是(A)、(B)、(D).对于其中的(D)选项,也就是对变压器副线圈中电流的求解,引起了极大的争议.解法1:由于副线圈的两个负载电阻并联,加之负载电
Problem. In the circuit shown in Figure 1, the ideal transformer primary and secondary windings have a turns ratio n1:n2=22:5, the primary coil is connected to u1=220槡2sin100πt(V), and the resistance R1=R2=25Ω. , D is the ideal diode, the following is correct (A) The voltage across resistor R1 is 50V. (B) The reverse voltage of the diode should be greater than 50 槡 2V. (C) The input power of the primary coil is 200W. (D) The current through the secondary coil is 3A. This is the 8th question in the first survey of the 2013 Senior High School in Nantong City, Jiangsu Province. The reference answers are (A), (B), (D). D) The option, that is, the solution of the current in the secondary winding of the transformer, has caused great controversy. Solution 1: The two load resistors of the secondary winding are connected in parallel, plus the load electricity.