褐飞虱Nilaparvata lugens (st(?)l)种群稳定增长初期(8月初)田间成、若虫拟合为负二项分布,卵为截尾负二项分布。由此导出理论抽样数模式。成、若虫为n=(1/D~2)[(1/(?))+1/2.3854]或n=(t/D)~2(1/(?)+1/2.3854)。卵为n=(9.1777/D~2·(?))[1-P(1)]或n=(t/D)~2·(9.1777/(?))[1-P(1)]。应用改进的(?)回归法,求得成、若虫的理论抽样数模式为n=(1/D~2)[(7.4820/(?))+0.11(?)-1.322]或n=(t/D)~2·[(7.4820/(?))+0.11(?)-1.322)。应用Taylor指数法得到理论抽样数模式为n=0.9932/D~2)·(?)~(-0.26854)或n=(t/D)~2·0.9932(?)~(-0.26856) The population of N. lugens Nilaparvata lugens (st (?) L) grew steadily in the early stage (early August), the nymph fitted negatively to the binomial distribution, and the eggs were negative binomial distributions. The theoretical number of patterns is derived from this. N = (1 / D ~ 2) [(1 / (?)) + 1 / 2.3854] or n = (t / D) ~ 2 (1 / (?) + 1 / 2.3854). Eggs were n = (9.1777 / D ~ 2 · (?)) [1-P (1)] or n = (t / D) -2 · (9.1777 / (?)) [1-P (1)]. Using the improved regression method, the theoretical num ber of nymphs is n = (1 / D ~ 2) [(7.4820 / (?)) +0.11 (?) - 1.322] or n = (t /D)~2[[7.4820/(?))+0.11(?)-1.322). The theoretical model of the number of samples is obtained by the Taylor exponential method with the n = 0.9932 / D ~ 2 (?) ~ (-0.26854) or n = (t / D) ~ 2 · 0.9932 (-0.26856)