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举一个例子来说明,假定前面介绍的建筑物的参数如下:UA=950kJ/Hr·℃(500Btu/Hr·°F)A_W=18.6m~2 (200Ft~2)A_F=139.5m~2(1500Ft~2)τa=0.8h_(FE)=30.63kJ/hr·m~2·℃(1.5Btu/Hr·Ft~2·°F)h_(FG)=2.04kJ/Hr·m~2·℃(0.1Btu/Hr·Ft~2·°F)h_(WE)=20.42kJ/Hr·m~2·℃(1Btu/Hr·Ft~2·°F)C_E=18 990kJ/℃(10 000Btu/°F)C_(SW)=9 495kJ/℃(5000Btu/°F)C_(SF)=37 980kJ/℃(20 000Btu/°F)h_(WA)=0首先确定稳态温度(ω=0);假定我们不计到地面的损失。因此:|G_(TA)[ω=0]|=1,φ_(TA)[ω=0]=0如果没有太阳能的增益,并且没有辅助加热,则围墙的平均温度等于平均的环境温度。其次
To give an example to illustrate, suppose that the parameters of the building described above are as follows: UA = 950 kJ/Hr·°C (500 Btu/Hr·°F) A_W = 18.6 m~2 (200 Ft~2) A_F=139.5 m~2 (1500 Ft ~2) τa=0.8h_(FE)=30.63kJ/hr·m~2·°C(1.5Btu/Hr·Ft~2·°F)h_(FG)=2.04kJ/Hr·m~2·°C ( 0.1 Btu/Hr·Ft~2·°F)h_(WE)=20.42 kJ/Hr·m~2·°C (1 Btu/Hr·Ft~2·°F) C_E=18 990 kJ/°C (10 000 Btu/° F) C_ (SW) = 9 495kJ / °C (5000Btu / °F) C _ (SF) = 37 980kJ / °C (20 000Btu / °F) h _ (WA) = 0 first determine the steady-state temperature (ω = 0); Suppose we don’t count the loss to the ground. Therefore: |G_(TA)[ω=0]|=1, φ_(TA)[ω=0]=0 If there is no solar gain and there is no auxiliary heating, the average wall temperature is equal to the average ambient temperature. Secondly