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学习了2,3,5的倍数的特征后,徐老师给大家出了一道题目:从0,1,2,3,4,5,6这七个数中选出四个,组成同时是2,3,5的倍数的四位数,一共可以组成多少个这样的四位数?机灵的牛钟康马上站起来说:“根据同时是2,3,5的倍数的特征,我们可以一一进行列举。同时是2,3,5的倍数的数个位上一定是0,且各个数位上的数的和一定是3的倍数。根据这个特征,我们可以逐一进行列举1230,1320,2130,2310…”
After studying the characteristics of multiples of 2, 3, and 5, Xu teacher gave us a question: select four from 0, 1, 2, 3, 4, 5 and 6, and form 2 , Four times the number of three times the total number of four such a total number can make up? The clever Niu Jong Kang stood up and said: “According to the characteristics of the same time is a multiple of 2,3,5, we can eleven Listed at the same time is a multiple of 2, 3, 5, the number of bits must be 0, and the number of each digit must be a multiple of 3. According to this feature, we can list one by one 1230,1320,2130,2310 ... ”