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形如f(x)=ax+b/x(a,b>0,x为正数)的函数在时取得最小值 ,如果所给x的范围中不含时,往往要通过证明函数的单调性求其最小值,过程繁琐,如果通过拆分,把函数分为两部分,使它们同时达到最小值,则显得简单明了.
The function f(x)=ax+b/x (a, b>0, x is positive) takes a minimum value at time. If the given range of x is not included, it is often required to pass the monotony of the proof function. It is cumbersome to search for its minimum value, and if it is split, the function is divided into two parts so that they reach the minimum at the same time, it is simple and clear.